{"id":753,"date":"2016-05-22T19:59:46","date_gmt":"2016-05-22T18:59:46","guid":{"rendered":"http:\/\/mathsguyon.fr\/?page_id=753"},"modified":"2020-12-15T08:50:47","modified_gmt":"2020-12-15T07:50:47","slug":"developper-avec-identites-remarquables","status":"publish","type":"page","link":"https:\/\/mathsguyon.fr\/?page_id=753","title":{"rendered":"D\u00e9velopper"},"content":{"rendered":"

Exercices :<\/h2>\n

M\u00e9thode de travail :<\/span><\/strong><\/h2>\n

Pour que ces exercices soient utiles, vous devez les travailler avant par \u00e9crit, comme vous le feriez en devoir surveill\u00e9. Sans aide, ni cours.<\/i><\/b><\/span><\/h3>\n

Regardez ensuite la correction pour juger votre travail, trouver vos \u00e9ventuelles erreurs, en essayant de bien les analyser.<\/i><\/b><\/span><\/h3>\n

Exercice 1 :<\/span>
\n<\/b><\/h2>\n

D\u00e9velopper $$(x + 5)^2$$ \u00a0\u00a0 Correction<\/a><\/h2>\n

D\u00e9velopper $$(2 x – 3)^2$$ \u00a0\u00a0 Correction<\/a><\/h2>\n

D\u00e9velopper $$(5 x – 4)(5 x + 4)$$ \u00a0\u00a0 Correction<\/a><\/h2>\n

Exercice 2 :<\/span><\/b><\/h2>\n

D\u00e9velopper : A = $$(6 + x) ^2$$\u00a0\u00a0\u00a0 ; B =$$(5 a – 2) ^2$$\u00a0\u00a0 ;<\/h2>\n

C = $$(2 x – 5) (2 x + 5)$$<\/h2>\n

D =<\/i> $$(6 x + 7)^2$$\u00a0\u00a0 ; E = $$(14 x -13)^2$$\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Correction <\/a><\/h2>\n

Exercice 3 :<\/b><\/span><\/h2>\n

D\u00e9velopper et r\u00e9duire :<\/h2>\n

A= $$(4 – x)^2- (x + 3)(2 x – 4)$$\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Solution seule<\/i>\u00a0\u00a0\u00a0 <\/i><\/a>–<\/i>\u00a0\u00a0\u00a0 <\/i><\/h2>\n

Correction d\u00e9taill\u00e9e<\/i><\/a><\/h2>\n

F = $$(5 x – 2)^2 – (3x – 1) (x – 2)$$ \u00a0\u00a0 \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 Correction<\/a><\/h2>\n

A = $$7x – (6x + 2)^2$$\u00a0\u00a0\u00a0 B = $$(6x – 4)^2 – (2x – 6)^2$$ \u00a0\u00a0 \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0 Correction A et B<\/a><\/h2>\n